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Solutions can be solid solutions e.g. alloys; liquid solutions e.g. lemonade and gaseous solutions e.g. air. A solution is made up of solute and solvent. Amount of solute The solution is homogeneous and does not settle. A solution cannot be filtered but can be separated using the process of distillation. For example, a solution of sugar in water. The particles are larger than the particles of solution and can be filtered. A suspension settles when it is allowed to stand for some time. The particles can be seen with the naked eyes. It does not separate out on standing and cannot be filtered. Colloids show the Tyndall effect. Light passing through a colloid shows dispersion. It is homogeneous to naked eyes, e.g. milk. Types of Colloids They do not scatter a beam of light, the particles do not separate by filtration and the particles do not settle down. The particles cannot be filtered. The size of particles is between 10 -7 cm to 10 -4 cm in diameter. Stir the content with a glass rod. Common salt dissolves completely to form a true solution. The sugar dissolves in water to form true solution. The alum dissolves in water to form a true solution. Stir well using a glass rod. Allow it to stand for some time and record your observation. (It does not dissolve in water) Stir the mixture with a glass rod. Allow it to stand for sometime record your observation. (Soil does not dissolve in water but forms a suspension) Now take 90 mL of hot, boiling water. (Heat the water in beaker using Bunsen burner) Stir the contents of the china dish continuously and pour the contents in the boiling water. Allow the contents to cool.Break an egg and discard the egg shells. Separate the white portion of egg from the yellow part. Add a very small quantity of egg albumin to it. Stir the contents thoroughly with the help of a glass rod.Paste a white paper with tick mark on one side of each test tube. Look at the tick mark through the contents of the three test tubes from the other side.

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Check for the transparency of tick mark. Record your observations. Fix the filter paper in the funnel and check for the filtration criterion.Record your observations. Shake all the test tubes and keep them in the test tube stand, allow it to stand for 5 minutes. Record your observations. Use it wisely. Answer: Air. Answer: Alloys: Brass—30 Zinc and 70 copper. Answer: Soda water, solute is C0 2, solvent is water. Answer: The size is less than 1 nm (10 -9 metre) in diameter. Answer: Due to very small particle size, it does not scatter a beam of light. Answer: By centrifugation. Answer: Aerosol, foam, emulsion. Answer: Fog, mist. Answer: Shaving cream, rubber. Answer: Milk, face cream. Answer: The amount of solute present in a given solution. Question 16: Give the chemical formula of sugar and alum.Answer: It is a colloidal solution. Answer: A solution which cannot dissolve more solute at a given temperature is called a saturated solution. A solution which can dissolve more of the solute at a given temperature is called an unsaturated solution. Answer: The protein in egg albumin coagulates to form a lump in hot water. Answer: A solution in which water is the solvent. Answer: Suspensions are used in medicines. Answer: The medium in which a colloid is formed is called the dispersing medium. The insoluble component in the medium is called the dispersed phase. Answer: Water, acetone, alcohol. Answer: Water is called universal solvent as maximum number of substances dissolve in it. Answer: Saturated solution on heating becomes unsaturated. Answer: In foam, the dispersing medium is liquid and dispersed phase is gas—for e.g. shaving cream. Or When dispersing medium is solid and dispersed phase is gas then foam is formed for e.g., rubber, sponge. Calculate its concentration in terms of mass by mass percentage of the solution. Answer: The solution will become unsaturated, because the solubility increases with the rise in temperature.

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Answer: The particles of true solution are very small to be seen with naked eye. Answer: The particles with the size order of 1000 nm or more are visible through our naked eye. Answer: Homogeneous mixture: can be separated by evaporation, distillation and fractional distillation. Heterogeneous mixture: can be separated by filtration, centrifugation, sedimentation and decantation. Answer: A beam of light will pass straight without scattering in case of true solution. When the suspension is settled it will not disperse the beam of light flashed on it but when the suspension is not settled the beam of light will scatter and the path of light will become visible. Answer: When light is flashed on the colloidal solution of sulphur it will be scattered. Answer: The size of particles in true solution is less than lnm, the size of colloidal particles is in the range of lnm to 1000 nm and the size of suspension particles is more than 1000 nm. The student observed that: (a) a transparent solution is formed (b) a translucent mixture is formed (c) egg white settles down at the bottom (d) egg white floats on the surface. The correct observation is (a) A, B, D are suspension (b) B, C, D are suspension (c) C, B, A are suspension (d) A, B, D are not suspension. The correctly reported set of observation is Appearance Stability Sedimentation (a) opaque unstable sediment (b) opaque stable sediment (c) Transparent unstable no sediment (d) Transparent stable no sediment The wrong conclusion made by him for both the solutions is: (a) Translucent (b) Shows Tyndall effect (c) Homogeneous and stable (d) Components cannot be separated by ordinary fdtration True solution and colloid are stable. The spring balance should be checked for any error. Let the zero error be 'x'. Measure the weight of the bob.The bob should not touch the base, nor the sides of the cylinder.Answer: Density is defined as the mass per unit volume.

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Answer: To find mass I will use a beam balance and to find weight I will use a spring balance. Answer: It can be measured by using spring balance. What is its least count. If its dimensions get doubled what will happen to its volume.Answer: The spring gets stretched due to the force exerted on it, this stretching produced is directly proportional to the stretching force. Answer: 0-10 N has 10 divisions hence each division mark indicates 1 N. Hence, the zero error is 2 N. Answer: With the decrease in the temperature, the density of water decreases. Which one will you choose. Answer: I will choose the spring balance which has the minimum value of least count to get accurate readings. Answer: The spring balance should be held only at the hook on the top end, never hold the spring balance from its sides. Give reasons in support of your answer. Answer: The density of the porous solid cannot be found by using measuring cylinder and spring balance. This is because the mass of solid when immersed in water will increase instead of decreasing as it will absorb water and amount of water displaced by the porous solid will be affected. Answer: The air bubble in the liquid taken in the measuring cylinder for an experiment will affect the volume of the solid because the air bubble occupies some space in the liquid and this increases the volume of the liquid. What happens to its density. Give reasons. Answer: The density in both the cases will be same because the mass remains the same and the volume of the water displaced by the metal cylinder and the cube remains the same. Pick the one you will choose to find the density (a) 1 cc (b) 0.2 cc (c) 5 cc (d) 0.1 cc. The least count of the spring balance is (a) 2.5 gwt (b) 25 gwt (c) 0.25 gwt (d) 15 gwt.

The wrong step in the procedure is (a) (i) (b) (ii) (c) (iii) (d) (iv) The volume of the metal cube is (a) 24 cm 3 (b) 22 cm 3 (c) 20 cm 3 (d) 18 cm 3 The mass of the solid is (a) 40 g (b) 75 g (c) 51 g (d) 35 g The one with least count (a) 2.5 ml (b) 1.0 ml (c) 0.5 ml (d) 0.2 ml. From the given observations, the volume of water displaced by the solid is (a) 64 cc (b) 36 cc (c) 30 cc (d) 100 cc. Balance A has a range of 0 to 250 g while balance B has a range of 10 to 1000 g. The performed option for precise mass measurement would be to use the balance (a) A for both (b) B for both (c) A for aluminium cube and B for iron cube (d) A for iron cube and balance B for aluminium. If you are asked to select a best suited spring balance to determine its weight, then out of the following which one would you prefer. The sphere is made of an alloy of density 7 x 103 kg m -3 (a) Range 0-1000 gwt, Least count 5 gwt. (b) Range 0-500 gwt, Least count 2.5 gwt. (c) Range 0-250 gwt, Least count 2.5 gwt. (d) Range 0-100 gwt, Least count 1 gwt. The student calculated the density of the solid as (a) 2000 kg m -3 (b) 9000 kg m -3 (c) 8000 kg m -3 (d) 6000 kg m -3. The upthrust is more by denser liquids. Let this weight be Wr This loss in weight is due to buoyancy (W 2 ). Archimedes’ principle is verified. Use this overflow can for the experiment. Answer: Solids cannot flow, so they are not fluids. Answer: Yes, fluids exert pressure in all directions. Answer: The buoyant force acts in an upward direction. Answer: Anything that flows is called a fluid. All liquids and gases are fluids. Answer: While swimming, water (fluid), exerts an upward force on the body this is called upthrust or buoyant force, because of this buoyant force we feel light. Answer: The magnitude of the buoyant force depends on the density of the fluid. Answer: When the upward force acting on the bottle is more than the downward force acting on the bottle then it will float.

Answer: The downward force is due to the gravitational attraction of the earth. When immersed in water nail sinks but cork floats. Why? Answer: This is because the density of cork is less than iron nail, it is also less than water density. Hence the upward force exerted by water on cork is much greater than the density of the cork, so it floats on water. In which case he finds swimming easier.Answer: When a body is immersed fully or partially in a fluid, it experiences an upward force that is equal to the weight of the fluid displaced by it. Answer: The density of liquids can be determined by hydrometer, it is based on Archimedes’ principle. Answer: Lactometer. Answer: The relative density of a substance is the ratio of its density to that of water. Answer: It has no unit, as it is a ratio of similar quantities. Answer: When the spring balance with stone is immersed in water, the stone experiences an upward force called buoyant force. It is due to this property the spring balance pointer moves up to show the loss in weight due to buoyancy. Answer: The buoyant force acting on an object immersed in a fluid depends on the density of the fluid and the volume of the fluid displaced by a body. Answer: The stone when immersed in salty water will displace water with more mass than as compared to the tap-water (density of salty water is more as compared to tap-water). Answer: The two precautions to be observed while making use of an overflow-can are: What will be the change in the apparent loss in the observed weight as the object is immersed in water. Answer: The object when immersed in water will gradually go on decreasing its weight and displaces water. The apparent weight loss will increase as the object is immersed in water. Is it different from a liquid or from a gas or from a solid. Answer: Fluid is a substance that can flow. Gases and liquids can flow but solids cannot, hence all liquids and gases are called fluids.

Answer: The measuring cylinder with the least count 1.0 ml will give more accurate reading. Answer: The eye level and the liquid level should be the same and the lower meniscus of the liquid should be read as its volume. Which of the bottle will be heavier. Give reason for your answer. Answer: The bottle with glycerine would be heavier because its mass is greater than water. The density of the substance is directly proportional to the mass of the body. With the increase in the temperature its density will decrease gradually. Answer: The density of sea water is more than the pool or river water. The buoyant force exerted by the sea water on a body is more and it keeps the body more afloat and less immersed and helps in swimming. Answer: Loss in weight of a solid depends on the weight of the liquid displaced and density of liquid. As the density of glycerine is more than the kerosene the loss in weight of a body in glycerine will be more as compared to kerosene. Answer: The same experiment for a body with density less than the liquid can be performed by using an object with known density, mass and volume as sinker can be tied to the light object. This way the density can be calculated. Answer: The recording of the readings needs lot of precision and the least count of the objects used should be the minimum. The thread used for tying the objects may also interfere in the accuracy. Answer: The solid should have more density than glycerine. He finds that there is a maximum apparent loss in weight of the body when (a) it just touches the surface of the liquid (b) it is completely immersed in the liquid (c) it is partially immersed in the liquid (d) it is partially immersed and also touches the sides of the container. It is then weighed by immersing it fully, in each of the given vessels filled with water. The weight indicated by the spring balance will be (a) least in vessel C (b) least in vessel B (c) least in vessel A (d) equal in all three vessels.

The result obtained will be wrong for (a) Student A (b) Student A (c) Student A (d) All three students The correct observation is (a) it sinks more in pure water (b) it sinks more in salty water (c) it sinks at same level in both (d) it floats in both. The mass of solid is He observed the water level till the ice melts completely in water. As per his observation when ice was added to water, the level of water (a) increased (b) decreased (c) remains the same (d) depends on shape of ice. The ship made of this iron floats on water due to (a) less density of ship than water (b) increased surface area increases the pressure (c) the downward force is balanced by the upthrust (d) all of the above. It is then weighed separately by immersing it fully in a vessel containing tap water and then in vessel containing salt solution. The reading of the spring balance would be (a) least in air (b) least in water (c) least in salt solution (d) equal in all three cases. The buoyant force experienced by the solid bob is (a) 9 N (b) 10 N (c) 1 N (d) 19 N. Answer: Vibration produces sound. Answer: Due to the vibration of vocal cords. Answer: The repeated reflection of sound that results in the persistence of sound is called reverberation. Answer: By using sound absorbing materials like curtains, draperies, ceiling with fibre boards etc. Answer: The audible range of sound is 20 Hz to 20,000 Hz. Answer: Rhinoceroses, whales, and elephants. Answer: Rats and bats. Why? Answer: Yes, sound travels in a wave which causes disturbance in the medium particles, set them in motion and wave travels. Answer: As sound waves set the particles of the medium in motion so they are called mechanical waves. Answer: Speed of sound depends on the media in which it is travelling. Speed of sound is higher in solids, and lower in liquids and least in gases. Answer: Yes, the speed of sound increases if the temperature of the medium is increased.

Answer: Yes, to hear the reflection of sound (echo) the time interval between the original sound and the reflected sound must be at least 0.1 second. Answer: The reflecting surface should be at the distance of 17.2 nr from the person who would like to hear his echo distinctly. Answer: The narrow tube B is suitable for stethoscope as multiple reflection is more and sound can be heard distinctly. Answer: In megaphones, curved ceilings or walls of the concert hall helps in creating multiple reflections of sound. Answer: The sound with frequency less than 20 Hz are called infrasound waves. The sound with frequency higher than 20 kHz are called ultrasound waves. Answer: To avoid the diffraction of sound and make its flow unidirectional long tube is used. The small diameter of the tube allows the selected sound wave to travel clearly. Answer: For reflection of light we need to take a polished and smooth surface but not transparent whereas for the reflection of sound the surface may not be polished and may be transparent. For sound reflection we need to choose such materials which do not absorb sound. Hence the wooden board will be used. What changes do you expect in observations. Answer: Speed of sound is faster in water than in air. Hence the sound will travel faster and the diffraction of sound is less. Answer: The low amplitude sound wave will travel with less energy and can be heard distinctly on reflection. But if we take high amplitude sound source the sound reflection will not be that distinct. Answer: The inside of the pipe can be made rough or fixed with the sound absorber to absorb all unwanted sound. The experiment is more likely to get performed successfully if the screen is a (a) rigid board (b) wooden board with many holes in it (c) foam padded board (d) sheet of cloth. A student can do his experiment to verily the laws of reflection of sound successfully by choosing the apparatus labelled as (a) A, C, D, E (b) A, C, E (c) A, B, D, E (d) A, C, D.

The correct measurement of the angle of incidence and angle of reflection has been done by the student (a) A (b) B (c) C (d) D. This shows that (a) angle of incidence is less than the angle of reflection (b) angle of incidence is greater than the angle of reflection (c) incident wave, normal and the reflected wave lie in the same plane. (d) sound waves do not obey laws of reflection. With the help of this, they can easily perform the experiments listed in the Lab Manual. Before they perform the experiments, every experiment’s basic concept section helps them know the aim of the experiment and achieve the result with fewer mistakes. Their basics will become strong as they will learn by doing experiments. That’s why we are providing a Class 9 Science Lab Manual for practice purpose to obtain a great score in the final examination. You can download the CBSE Class 9 Science Lab Manual in PDF Format for better preparation. To know more about the Deleted Chapter in Syllabus Click Here. The student is advised to check out to complete summary. You can visit all these important topics by clicking the links given. First, of all, check the CBSE Class 9 Science Exam Pattern. Students are advised to check out the complete syllabus and exam pattern with the marking scheme. Students can check the Class 9 Science Exam Pattern for the academic year 2020-21. Students are advised to check the Complete Science for 9 Class. Students have to download the complete Class 9 Science Lab Manual in pdf for the great score in the final examination. Click Here Unit 2 The World of Living To prepare a stained, temporary mount of onion peel and to study its cells. Click Here You can visit all these important topics by clicking the links given.? Students may apply for the Scholarships at the beginning of the academic year. Merit cum means based scholarships are also awarded by the college to deserving students.You can see the Olympiad Exam.

Elements: An element consists of only one type of particles. Q. What is the matter in chemistry class 9? A. Matter- Matter is anything which occupies space and has mass is called matter. Air and water, sugar and sand, hydrogen and oxygen etc. The matter is made up of very small tiny particles. Particles of matter have space between them they attract each other. Q. What is the meaning of ICT? A. Information and communications technology (ICT) is an extensional term for information technology (IT) that stresses the role of unified communications and the integration of telecommunications (telephone lines and wireless signals) and computers, as well as necessary enterprise software, middleware, storage. Q. Is 9th class important for Board points of view? A. Every class in your academics are important. The most important reason why class 9th is important is: that you have to pass class 9th to appear for the board exams in class 10th. The third reason why class 9th is important is: that the continuation of class 9th is in class 11th, so you will get the basics cleared in class 9th itself. Q. How do I score 100 in class 9? A. 1. Make detailed notes for every chapter in your own handwriting. 2. Do revise those notes at regular intervals. 3. Solve all questions multiple times 4. Students are going to coaching or not self-study matters a lot. 5. Get good study materials other than your textbooks. 6. Try to teach what you have learnt to your friends and others, this will help to understand better. 7. Don’t make any doubt in your mind to be not clear. Edufever does not hold responsible for anything inappropriate or wrong information given by the advertiser. Ask Here for Quick Answer, Note: Write question with complete details for better answers She has a bachelors degree and currently doing PGDM in Digital Marketing. Loves Writing, Drawing, Reading, Dancing and Travelling. ERF Awards get initiated when we get nominations from Colleges, University and Educational institutes.

I want to thank the Edufever family for creating a bright career.? Staff members and counsellors are very professional, kind and helpful. Proud to be a part of the Edufever Family. College clubs and organizations are home for the extracurricular activities, and this can highlight your free time on campus. The simple, but powerful user-interface highlights essential information. You will receive a link to create a new password via email. Welcome to our exclusive page for CBSE Class 9 Online Study Materials. As we all know that CBSE NCERT amends and update its curriculum very often to make necessary changes in the syllabus. So it is always a wise decision to keep track of the ever-changing study curriculum. In this article, you will get the Download CBSE Class 9 Syllabus, Sample Papers, Worksheet, Previous year Question Papers, NCERT Solutions etc. To know more about the Deleted Chapter in Syllabus Click Here. Scholarships Scheme 12. Olympiad Exam 2020-21 13. Frequently Asked Questions 14. CBSE Useful Resources These education resources will help you to prepare for your examination studies in full swing. Our Library consists of the updated syllabus, subject-related books, Sample papers and subject NCERT Solutions absolutely free. Yes, you heard it right.Before we discussed Class 9 Study Material, let us check the CBSE Class 9 Summary; Below, we have mentioned the complete CBSE Class 9 Summary. The student is advised to check out to complete the summary. The Hindi study materials are for the academic year 2020-21 session.The English study materials are for the academic year 2020-21 session.The Mathematics study materials are for the academic year 2020-21 session.The Science study materials are for the academic year 2020-21 session.The SST study materials are for the academic year 2020-21 session.The Sanskrit study materials are for the academic year 2020-21 session.Computer study materials are for the academic year 2020-21 session.

These books will provide you with practice sets and examples based on the concept you learnt from NCERT Books. Let us check out. Students can download the complete Subject wise holiday homework in PDF Format for practice purpose. Students may apply for the Scholarships at the beginning of the academic year. Merit cum means based scholarships are also awarded by the college to deserving students.You can see the Olympiad Exam. The only difference is that students of school-conducted examination appear in their own school whereas those of Board conducted appear in the allotted centre. The answer copies of Board-conducted examination are centrally evaluated at designated centres whereas those of school-based, by the school teachers based on the marking schemes supplied by the Board. Q. Will the results for CBSE Class X and School-Based Exams SA2 be announced at the same time or separately. Is there any discrimination for admission in class XI? A. The results for the CBSE-conducted and school-conducted Summative Assessment examination will be declared at the same time. As far as the CBSE is concerned, there is no discrimination between students who opt for Board-conducted examination or school-conducted examination for admission to Class XI. Edufever does not hold responsible for anything inappropriate or wrong information given by the advertiser. Ask Here for Quick Answer, Note: Write question with complete details for better answers She has a bachelors degree and currently doing PGDM in Digital Marketing. Here are all questions are solved with a full explanation and available for free to download. NCERT Class 9 Book for Science Lab Manual (English) are given below. We hope that our NCERT Class 9 Book for Science Lab Manual (English) helped with your studies. If you liked our NCERT Class 9 Book, please share this post.

You might be informed of that the curriculum for all schools that obey the CBSE is set by the National Council of Education Research and Training across the state. The NCERT Book for Class 9 Science Lab Manual (English) provided on SelfStudys have been written to help you know all the chapter-wise problems in the syllabus prescribed by CBSE. The NCERT Class 9 Book for Science Lab Manual (English) PDF help students solve the exercises presented in the textbooks and get good marks in their board examination. Not only that, but you will also have access to all the study materials and solutions along with absolutely Online Tests to improve your problem-solving speed. Indeed, Science Lab Manual (English) forms a vital part of Class 9 as well as every competitive exams syllabus. Whether you select to be a doctor or engineer, you will have to deal with Science Lab Manual (English) in every area. Making the concepts of class 12 concrete can immensely help you in obtaining good marks in the CBSE Class 9 board examination as well as in different competitive exams. NCERT Class 9 Book for Science Lab Manual (English) plays an important role in your exam preparation. First, you should imprint this in your mind that NCERT books are the most important tool that you can have to get well-versed with the basics. Getting a good grip over exhaustive parts of some chapters of Science Lab Manual (English) can be of great help while learning the derivations and concepts behind the numerical of Science Lab Manual (English). You can simply download NCERT Class 9 Book for Science Lab Manual (English). The solutions for every exercise have been curated and evaluated by some of the best educators across India. It includes all the answers to the questions from 13 major chapters from the NCERT Science Lab Manual (English) textbook. NCERT Class 9 Book Science Lab Manual (English) covers crucial and intricate chapters.

The chapters are designed in a logical manner, which allows you to know the concepts easily. The NCERT Class 9 Book for Science Lab Manual (English) PDF Download is available on this website for FREE which you can check anytime, anywhere. As a fact, scientists have discovered that a numbering system was also used by the Indus Valley culture. They used this essentially for trade and commerce purposes with various parts of the world. Today, Science Lab Manual (English) holds a very important position in almost all aspects of our life. For instance, at the supermarket billing counter, we inevitably use the digital numerical system to calculate our total bill. The NCERT Class 9 Book for Science Lab Manual (English) has been curated and evaluated by some of the best Science Lab Manual (English) teachers in the nation to help students understand all the fundamental concepts. It is an excellent guide that can be used to prepare for the CBSE Board examinations, as well as other competitive entrance exams such as JEE and NEET. The NCERT Class 9 Book for Science Lab Manual (English) are very helpful during studies, teaching students how to best approach a difficulty. The NCERT Class 9 Book for Science Lab Manual (English) is an aid that should complement the student's school textbook and help them know the problems in a much better manner. One of the best benefits NCERT Solutions is it acts as a specialist tool which can be used as a gateway to the understanding of the examiner. It provides a complete view of the prescribed syllabus, as the textbook doesn't have a detailed description of the syllabus nor solutions. All the important theorems of Class 9 are completely solved, which works to make the concepts and find new links to them. When the NCERT book is accompanied by the solutions, the knowledge of concepts becomes simple and in-depth. Moreover, students can trail into the solutions without break in topics, as it is designed to give a step-by-step explanation.